Python Markov Chain Generator

[ddthj]

So I spent 3 hours making a messy markov chain generator in python, and since it was a pain to do I figured I'd post it here so no one else has to go through the trouble

This takes a text input prompt but you could use any method to give it text.

The generator keeps track of:
words,
what words come after other words,
the amount of times a word has come after another word.

Brain format:

brain{  word :[  [other word, times found], [other word, times found]  ],    word :[  [other word, times found], [other word, times found]  ] }

kindof a mess, but hey if it works it works :)

Code:

brain = {} #making the main dict
text = input('Please enter a sentence.\n') #getting some text
text = text.lower() #making the text less variable

words = text.split(' ') #splitting the text into words
wordlen = len(words) #finding the number of words
print(words)
print(wordlen)
itemcount = 0
for item in words:
    hit = False
   if itemcount >= len(words)-1: #making sure we don't loop through the last word because that will throw an error
       break
   if item in brain: # if the item already exists, we do this:
       nextitem = words[int(itemcount)+1] #find the word after this one
       b = brain[str(item)] #make a name for the list of words that come after the current word we are on
       for mylist in b:
           if str(mylist[0]) == str(nextitem): #check to ensure we don't duplicate a word
               count = int(mylist[1]) #if the following word already exists, we add 1 to the number of times it has appeared after the current word in question
               count += 1
               mylist[1] = count
               hit = True
       if hit == False: #if we have never seen it come after the current word, we add it
           newlist = [str(nextitem), 1]
           b.append(newlist)
           
   else: #for when the item doesn't already exist
       brain[str(item)] = [] #make the item
       nextitem = words[int(itemcount)+1]
       b = brain[str(item)]
       for mylist in b: #go through same process as before with finding words that come after it
           if str(mylist[0]) == str(nextitem):
               count = int(mylist[1])
               count += 1
               mylist[1] = count
               hit = True
       if hit == False:
           newlist = [str(nextitem), 1]
           b.append(newlist)
           
   itemcount+=1
   

print(str(brain))