06-26-2013, 06:18 AM
So, I have found that:
n^2 = (n-1)^2 + 2(n-1) + 1
(n+1)^2 = n^2 + 2n +1
is this essentially what you are saying?
n^2 = (n-1)^2 + 2(n-1) + 1
(n+1)^2 = n^2 + 2n +1
is this essentially what you are saying?