Let the digits of the number be contained in the n-dimensional vector a, like this:
which is equivalent of the binary number 10011101.
Given the base
(2 in this case), the number in decimal can be found using the following equation:
} \cdot b^{(i-1)})
So we can conclude, that this is true:
} \cdot 2^{(i-1)}} = 157)
(05-11-2013, 10:39 AM)David Wrote: [ -> ]Wait, wut?
Same here. We're probably not that far into logic & formula's
Lol, nice use of sigma notation to confuse people
.
I think you've got your vector backwards. If you're indexing the digits like in a typical array, the index would be increasing from left to right, so you would get 185 not 157. You'd have to use
)
to get that.
Thank you, didn't think about that. Fixed.
*Hits, 'That was easy' button*
Oi, leave my buttons alone!
I understood it until you brought the equation, maybe I should go to school for a few more years.